The equation of a curve is such that $\dfrac{dy}{dx} = 4(2x-5)^3 - 9x^{\frac{1}{2}}$. The curve passes through the point $A\left(4, -\frac{11}{2}\right)$.
**(a)** Find the gradient of the normal to the curve at the point *A*.
The equation of a curve is such that $\dfrac{dy}{dx} = 4(2x-5)^3 - 9x^{\frac{1}{2}}$. The curve passes through the point $A\left(4, -\frac{11}{2}\right)$.
The diagram shows the curve with equation $y = 5x^{\frac{3}{2}} - 20x$ and the line with equation $y = x - 16$. The $x$-coordinates of the points of intersection of the curve and line are 1 and 16.
Find the area of the shaded region between the curve and the line.
**(a)** Find the first three terms, in ascending powers of $x$, in the expansion of each of the following expressions.
**(b)** Given that the coefficient of $x^2$ in the expansion of $(2 - px)^5\left(1 - \frac{1}{2}x\right)^4$ is 93, find the possible values of the constant $p$.
(In part (a) you found $(2 - px)^5 = 32 - 80px + 80p^2x^2 + \ldots$ and $\left(1 - \frac{1}{2}x\right)^4 = 1 - 2x + \frac{3}{2}x^2 + \ldots$)
The diagram shows a sector $ABC$ of a circle with centre $A$ and radius $r$ cm. The angle $BAC$ is $\alpha$ radians, where $0 < \alpha < \frac{1}{2}\pi$.
**(a)** It is given that the area of the triangle $ABC$ is $4\ \text{cm}^2$ and the area of the sector $ABC$ is $8\alpha\ \text{cm}^2$.
The diagram shows a sector $ABC$ of a circle with centre $A$ and radius $r$ cm. The angle $BAC$ is $\alpha$ radians, where $0 < \alpha < \frac{1}{2}\pi$.
**(b)** It is given instead that the length of the chord $BC$ is $\dfrac{1}{\sqrt{2}}r$ cm but the area of the triangle $ABC$ is still $4\ \text{cm}^2$.
Find the area of the shaded segment. Give your answer correct to 3 significant figures.
**(a)** Describe fully a sequence of transformations which transforms the graph of $y = \mathrm{f}(x)$ to the graph of $y = \mathrm{g}(x)$. You should make clear the order in which the transformations are applied.