Question 15
The equation of a curve is such that $\dfrac{d^2y}{dx^2} = -\dfrac{24}{x^3}$. It is given that the curve has a stationary point at $(-2, 19)$.
**(a)** Find an expression for $\dfrac{dy}{dx}$.
**(a)** Find an expression for $\dfrac{dy}{dx}$.
