Question 43
The diagram shows a quadrilateral *OXPY* with diagonals meeting at *T*.
$\overrightarrow{OX} = 3\mathbf{a}$ and $\overrightarrow{OY} = 12\mathbf{b}$.
**(b)** *XT* : *TY* = 1 : 2 and $\overrightarrow{YP} = 5\mathbf{a} - 2\mathbf{b}$.
Find the ratio *OT* : *TP*.
(In part (a) you found $\overrightarrow{XY} = -3\mathbf{a} + 12\mathbf{b}$.)
(Type like 4 : 5)
